Virtual function inside private access specifier.

There will not be any error, see the below mentioned program and output.

#include<iostream>
using namespace std;

class Base
{
    public:
        virtual void displayClassName()
        {
            cout<<"base class"<<endl;
        }
};

class Derived : public Base
{
    private: // notice displayClassName function is private in derived class.
        virtual void displayClassName()
        {
            cout<<"Derived class"<<endl;
        }
};
int main(int argc, char **argv)
{
    Base *ptr;
    Derived obj;
    ptr = &obj;
    ptr->displayClassName();
    return 0;
}

/*
------------------------------------------------------output
$ ./a.exe
Derived class
*/

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